Math: Check divisibility

check-divisibility.py

#!/usr/bin/env python

import math, time

# 01. All whole numbers are multiples of 1
# 02. The last digit is 2, 4, 6, 8, 0
# 03. The digits add up to a multiple of 3
# 04. The last 2 digits are a multiple of 4
# 05. Last digit is either 5 or 0
# 06. Divisible by 2 and 3
# 07. It is a bit bizarre. Use google. You may get confused
# 08. Last 3 digits are divisible by 8
# 09. The digits add up to a multiple of 9
# 10. So obvious - ends in 0

_num = 2520
_pieces = [int(i) for i in str(_num)]

def d2():
  global _pieces, num
  return _pieces[-1] in [0, 2, 4, 6, 8]

def d3():
  if sum( _pieces ) % 3 == 0:
    return True
  else:
    return False

def d4():
  if int( ''.join( [str(i) for i in _pieces[-2:]] ) ) % 4 == 0:
    return True
  else:
    return False

def d5():
  return _pieces[-1] in [0, 5]

def d6():
  if d2() and d3():
    return True
  else:
    return False

def d7():
  s1 = int( ''.join( str(i) for i in _pieces[:-1] ) )
  s2 = _pieces[-1] * 2
  s3 = s1 - s2
  s4 = [int(i) for i in str(s3)]
  s5 = int( ''.join( str(i) for i in s4[:-1] ) )
  s6 = s4[-1] * 2

  if ( s5 - s6 ) % 7 == 0:
    return True
  else:
    return False

def d8():
  if int( ''.join( str(i) for i in _pieces[-3:] ) ) % 8 == 0:
    return True
  else:
    return False

def d9():
  if sum( _pieces ) % 9 == 0:
    return True
  else:
    return False

def d10():
  if _pieces[-1:][0] == 0:
    return True
  else:
    return False