$3x^2-5x+2=x^2+x+2$2; 34; 51; -2$x^2+3x+1=x+1$$3(1+2x^2)=3x^2-5(4x^2-1)$
$\sqrt{5x+1}+\sqrt{x+6}=\sqrt{2x+3}+\sqrt{6x-2}$$\sqrt{2x+14}-\sqrt{3x+1}=2$$\sqrt{x+7+\sqrt{x+10}}=3$
$$\frac 23$$
$3x^2-5x+2=x^2+x+2$2; 34; 51; -2$x^2+3x+1=x+1$$3(1+2x^2)=3x^2-5(4x^2-1)$$\sqrt{5x+1}+\sqrt{x+6}=\sqrt{2x+3}+\sqrt{6x-2}$$\sqrt{2x+14}-\sqrt{3x+1}=2$$\sqrt{x+7+\sqrt{x+10}}=3$$$\frac 23$$