Created
February 2, 2025 03:20
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def MaxContiguousSubarray(A): | |
currMax = 0 | |
currSum = 0 | |
for i in range(len(A)): | |
currSum = max(currSum + A[i], A[i]) | |
currMax = max(currMax, currSum) | |
return currMax | |
def MaxsumSubseq(M): | |
currMax = 0 | |
l = len(M[0]) | |
for i in range(l): | |
currMax = max(currMax, | |
MaxContiguousSubarray(M[i]), #Horizontal | |
MaxContiguousSubarray([M[j][i] for j in range(l)]), #Vertical | |
MaxContiguousSubarray([M[l - j - 1][i - j - 1] for j in range(i + 1)]), #Diagonal | |
MaxContiguousSubarray([M[i + j][i + j] for j in range(l - i)]), #Diagonal | |
MaxContiguousSubarray([M[l - j - 1][l - i + j - 1] for j in range(i + 1)]), #Anti-Diagonal | |
MaxContiguousSubarray([M[j][i - j] for j in range(i + 1)]) #Anti-Diagonal | |
) | |
return currMax | |
def genM(): | |
M = [[0 for _ in range(2000)] for _ in range(2000)] | |
S = [0] + [0]*(4*10**6) | |
for k in range(1, 56): | |
S[k] = (100003 - 200003*k + 300007*pow(k, 3, 10**6)) % 10**6 - 500000 | |
for k in range(56, 4*10**6 + 1): | |
S[k] = (S[k - 24] + S[k - 55]) % 10**6 - 500000 | |
S.pop(0) | |
for i, s in enumerate(S): | |
M[i//2000][i % 2000] = s | |
print(MaxsumSubseq(genM()) |
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