Base 2 and Base 10 Converter Script Using Local Functions

base_converter.py

def converter(number, base):
    def convert_to_base_10(val):
        target_base = 10  # Target number base
        output_sum = 0  # Initial value for output sum
        expo = 0  # Initial exponent
        digits = [int(x) for x in str(val)] # Convert the base 2 number to an array of integer
        digits.reverse()  # Reverse the array.

        for d in digits:  # For each bit...
            if d != 0:  # If it's not 0, we will get the value relative to the position
                output_sum += pow(2, expo)  # Add it to the output
            expo += 1  # Move to the next bit

        return output_sum, target_base

    def convert_to_base_2(val):
        target_base = 2  # Target number base
        binary = []
        while True:
            reminder = val % target_base
            val = int(val / target_base)  # Force int truncation
            binary.append(reminder)  # Put the digit in the list

            if val > 0:
                continue  # We still need to divide
            else:
                break  # Nothing else to do

        binary.reverse()

        binary = list(map(lambda x: str(x), binary))  # Transform the int to an array of str

        return int(''.join(binary)), target_base

    if base == 2:
        return convert_to_base_10(number)
    elif base == 10:
        return convert_to_base_2(number)

if __name__ == '__main__':
    print("Converting from binary to decimal")
    print(converter(101110011, 2))

    print("Converting from decimal to binary")
    print(converter(708, 10))