A lazy sequence implementation of the fizzbuzz problem.

core.clj

(ns fizzbuzz.core)

(defn divisible [x n]
  (if (= 0 (mod x n))
    :true))

(defn nth-fizzbuzz-term [n]
  (cond (and (divisible n 3) (divisible n 5)) :fizzbuzz
	(divisible n 3) :fizz
	(divisible n 5) :buzz
	:else n))

(defn fizzbuzz [x]
  (lazy-seq (map nth-fizzbuzz-term (range 1 (inc x)))))

;; Example Usage
;; > (take 10 (drop 100000000 (fizzbuzz.core/fizzbuzz 1500000000)))
;; (100000001 :fizz 100000003 100000004 :fizzbuzz 100000006 100000007 :fizz 100000009 :buzz)

see what I did there?

…

--- Aaron Kuehler

On Nov 22, 2011, at 5:45 PM, Kyle ***@***.*** wrote: ew you said 'blow your stack.' --- Reply to this email directly or view it on GitHub: https://gist.github.com/1378338