CS450 style file

akteach.sty

\nonstopmode

\usepackage[letterpaper, margin=1in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage{xcolor}
\usepackage{url}
\usepackage{hyperref}
\usepackage{keystroke}
\usepackage{tikz}
\usepackage{ifthen}
\usetikzlibrary{topaths}
\usepackage{verbatim}
\usepackage{listings}
% \usepackage{amsmath}
\usepackage{enumerate}

\usepackage{fancyhdr}
\usepackage{extramarks}
\pagestyle{fancy}
\fancyhf{} % clear all header and footer fields
\fancyfoot[C]{\thepage} % except the center
\renewcommand{\headrulewidth}{0pt}%
\renewcommand{\footrulewidth}{0pt}%

\lhead{\firstxmark}
\rfoot{\lastxmark}

% Added by kk
\usepackage{amsmath, amssymb,amsthm}
\usepackage{natbib}
\usepackage{microtype}
\usepackage{mathtools}
\usepackage{xfrac}
%

\newboolean{issolution}
\setboolean{issolution}{false}
\newboolean{isalternative}
\long\def\altversion#1#2{\ifthenelse{\boolean{isalternative}}{#1}{#2}}

\def\weblink#1#2{\href{#1}{\underline{#2}}\footnote{\url{#1}}}

\colorlet{codeback}{gray!20}

% \lstset{
%   language=C++,
%   showstringspaces=false,
%   basicstyle=\small\sffamily,
%   stringstyle=\color{blue},
%   columns=flexible,
%   backgroundcolor=\color{codeback},
%   frame=single,
%   framerule=0pt,
%   framesep=1.5pt,
%   includerangemarker=false,
%   language=C++,
%   rangebeginprefix=/*\ ,
%   rangeendprefix=/*\ ,
% }

% Added by kk
\lstset{
language=Python,
numbers=none,
frame=single,
basicstyle=\normalsize\ttfamily,
commentstyle=\color[rgb]{0.7,0.2,0.2}\ttfamily,
keywordstyle=\color{blue},
showstringspaces=false
}

\lstdefinestyle{custompython}{
    belowcaptionskip=1\baselineskip,
    breaklines=true,
    % frame=single,
    xleftmargin=\parindent,
    language=Python,
    %showstringspaces=false,
    basicstyle=\footnotesize\ttfamily,
    keywordstyle=\bfseries\color{green!40!black},
    commentstyle=\itshape\color{purple},
    identifierstyle=\color{black},
    stringstyle=\color{orange},
    keywords=[2]{as,True,False},
    keywordstyle=[2]\bfseries\color{green!40!black},
    keywords=[3]{np,sp,plt},
    keywordstyle=[3]\bfseries\color{blue},
    numbers=none,
    columns=fullflexible,
}
%

\parskip=0.3em
\parindent=0pt

\newlength{\akteachheadboxwidth}
\setlength{\akteachheadboxwidth}{\textwidth}
\addtolength{\akteachheadboxwidth}{-6mm}

\def\akteachheader#1#2{
  \tikz \node [text width=\akteachheadboxwidth,fill=gray!20, inner sep=3mm]
  {
    \sffamily\bfseries
    \large
    #1
    \\[1ex]
    \huge #2
  } ;\\
}
\def\akteachsubheader#1{
  \tikz \node [text width=\akteachheadboxwidth,fill=gray!10,inner sep=3mm]
  {
    \sffamily\bfseries
    #1
  } ;
}
\def\akteachdue#1#2{
  \akteachsubheader{
    \sffamily\bfseries Due: #1
    \hspace*{1cm}
    \sffamily\bfseries Out: #2
  }
}
\def\akteachnamefield#1{
  \akteachsubheader{
    \vspace*{0.3cm}
    Name: \hrulefill #1
  }
}
\def\akteachprobhead#1{
  {\large\sffamily\bfseries #1}
}

\newtheorem{note}{Note}

\def\answerrect#1{\tikz\draw (0,0) rectangle ++(#1,2em) ++(0.5mm,2mm); }
\def\checkbox{\begin{tikzpicture}
    \draw [use as bounding box] (0,0) rectangle ++(1em,1em) 
      coordinate [pos=0.5] (x) ++(0.5mm,2mm);
  \end{tikzpicture}}
\def\checkedbox{\begin{tikzpicture}
    \draw [use as bounding box] (0,0) rectangle ++(1em,1em) 
      coordinate [pos=0.5] (x) ++(0.5mm,2mm);
    \ifthenelse{\boolean{issolution}}{ \node at (x) {X}; }{}
  \end{tikzpicture}}

\def\lanswerrect#1{\tikz \draw (0,0) rectangle (#1,1.25) node [above,anchor=south
east,inner xsep=0] { Answer };}
\def\solanswerrect#1#2{
  \begin{tikzpicture}
    \draw (0,0) rectangle (#1,1.25)
    node [pos=0.5] {\ifthenelse{\boolean{issolution}}{#2}{}}
    node [above,anchor=south east,inner xsep=0] { Answer };
  \end{tikzpicture}
}

\tikzset{
  solbox/.style={
    draw,fill=black!10, text width=0.9\textwidth,inner sep=3mm
  }
}
\long\def\smallsolbox#1{\colorbox[rgb]{.9,.9,.9}{#1}}
\long\def\solbox#1{%
  \smallsolbox{\begin{minipage}[t]{1\columnwidth}%
  #1%
  \end{minipage}}%
}


\long\def\textorsolbox#1#2{%
  \ifthenelse{\boolean{issolution}}{%
    \smallsolbox{\begin{minipage}[t]{1\columnwidth}%
    #2%
    \end{minipage}}%
  }{#1}%
}
\long\def\spaceorsolbox#1#2{%
  \ifthenelse{\boolean{issolution}}{%
    \smallsolbox{\begin{minipage}[t]{1\columnwidth}%
    #2%
    \end{minipage}}%
  }{\vspace{#1}}%
}

\long\def\qboxorsolbox#1#2{%
  \ifthenelse{\boolean{issolution}}{%
    \smallsolbox{\begin{minipage}[t]{1\columnwidth}%
    #2%
    \end{minipage}}%
  }{#1}%
}

% Added by kk
% New commands
\def\intd{\mathrm{d}}
\DeclareMathOperator{\cond}{cond}

\newcommand{\doi}[1]{\href{http://dx.doi.org/#1}{doi: #1}}
\newcommand{\cw}{\texttt}
\newcommand{\R}{\mathbb{R}}
\newcommand{\abs}[1]{\lvert#1\rvert}
\newcommand{\bm}[1]{\boldsymbol#1}
%

worksheet-01.tex

\documentclass[11pt]{article}

\usepackage{akteach}

\begin{document}

\akteachheader{Numerical Analysis (CS 450)}%
{Worksheet 1}

\akteachprobhead{%
  Problem 1: Forward/backward error
}

Consider the function $f(x)=1/x$, which we approximate by its Taylor
series about 1:
\[
  f(x)\approx 1-(x-1)+\cdots
\]
\begin{enumerate}[(a)]
  \item What is the forward error of using this approximation at
    $x=0.5$?
    \vspace*{2cm}
  \item What is the backward error of using this approximation at
    $x=0.5$?
    \vspace*{2cm}
\end{enumerate}

\akteachprobhead{%
  Problem 2: Condition number
}

\begin{enumerate}[(a)]
  \item
    Determine an approximate global upper bound on the condition
    number of evaluating $\sin(x)$ on the interval $[0,\pi/2]$.
    \vspace*{2cm}

  \item Is the condition number on the interval $[10^4\pi,10^4\pi
    +\pi/2]$ larger or smaller than in (a)?
    \vspace*{1cm}
\end{enumerate}

\akteachprobhead{%
  Problem 3: Condition number, again
}

Which of the operations $+,-,\times, /$ are, loosely, always `well-conditioned'?


\end{document}