Last active
December 20, 2015 09:19
-
-
Save inkhorn/6107312 to your computer and use it in GitHub Desktop.
Estimate Age from First Name in R
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
library(stringr) | |
library(plyr) | |
# We're assuming you've downloaded the SSA files into your R project directory. | |
file_listing = list.files()[3:135] | |
for (f in file_listing) { | |
year = str_extract(f, "[0-9]{4}") | |
if (year == "1880") { # Initializing the very long dataframe | |
name_data = read.csv(f, header=FALSE) | |
names(name_data) = c("Name", "Sex", "Pop") | |
name_data$Year = rep(year, dim(name_data)[1]) } | |
else { # adding onto the very long dataframe | |
name_data_new = read.csv(f, header=FALSE) | |
names(name_data_new) = c("Name", "Sex", "Pop") | |
name_data_new$Year = rep(year, dim(name_data_new)[1]) | |
name_data = rbind(name_data, name_data_new) | |
}} | |
year_pop_totals = ddply(name_data, .(Year), function (x) sum(x$Pop)) | |
name_data = merge(name_data, year_pop_totals, by.x="Year", by.y="Year", all.x=TRUE) | |
name_data$Rel_Pop = name_data$Pop/name_data$V1 | |
estimate_age = function (input_name, sex = NA) { | |
if (is.na(sex)) { | |
name_subset = subset(name_data, Name == input_name & Year >= 1921)} #1921 is a year I chose arbitrarily. Change how you like. | |
else { | |
name_subset = subset(name_data, Name == input_name & Year >= 1921 & Sex == sex) | |
} | |
year_and_rel_pop = name_subset[which(name_subset$Rel_Pop == max(name_subset$Rel_Pop)),c(1,6)] | |
current_year = as.numeric(substr(Sys.time(),1,4)) | |
estimated_age = current_year - as.numeric(year_and_rel_pop[1]) | |
return(list(year_of_birth=as.numeric(year_and_rel_pop[1]), age=estimated_age, relative_pop=sprintf("%1.2f%%",year_and_rel_pop[2]*100))) | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment