Created
April 9, 2020 06:19
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import sys | |
r, c, m = map(int, sys.stdin.readline().split()) | |
maps = [[0 for _ in range(c)] for _ in range(r)] | |
for _ in range(m): | |
y, x, s, d, z = map(int, sys.stdin.readline().split()) | |
maps[y-1][x-1] = (s, d-1, z) | |
dirs = [(-1,0),(1,0),(0,1),(0,-1)] | |
# 가장 가까운 거리의 상어 잡기 | |
def get_shark(column_idx, maps): | |
size = 0 | |
for idx in range(len(maps)): | |
if maps[idx][column_idx] != 0: | |
speed, dirs, size = maps[idx][column_idx] | |
maps[idx][column_idx] = 0 | |
break | |
return size | |
def move_sharks(maps): | |
new_shark = [[0 for _ in range(len(maps[0]))] for _ in range(len(maps))] | |
for y in range(len(maps)): | |
for x in range(len(maps[0])): | |
if maps[y][x] != 0: | |
speed, i, size = maps[y][x] | |
# 왕복 횟수 제거 | |
if i == 0 or i == 1: | |
speed %= ((2 * len(maps)) - 2) | |
elif i == 2 or i == 3: | |
speed %= ((2 * len(maps[0])) - 2) | |
ny, nx = y, x | |
# 시작부터 방향 반대로 바꿔줘야 하는 경우 | |
if ny == 0 and i == 0: | |
i = 1 | |
elif ny == len(maps)-1 and i == 1: | |
i = 0 | |
elif nx == len(maps[0])-1 and i ==2: | |
i = 3 | |
elif nx == 0 and i == 3: | |
i = 2 | |
# 상어 이동 | |
for _ in range(speed): | |
if i == 0: | |
ny -= 1 | |
if ny - 1 < 0: | |
i = 1 | |
elif i == 1: | |
ny += 1 | |
if ny + 1 >= len(maps): | |
i = 0 | |
elif i == 2: | |
nx += 1 | |
if nx + 1 >= len(maps[0]): | |
i = 3 | |
elif i == 3: | |
nx -= 1 | |
if nx - 1 < 0: | |
i = 2 | |
# 이동한 지점에 상어가 없거나, 자리잡은 상어보다 크기가 큰 경우 | |
if new_shark[ny][nx] == 0 or size > new_shark[ny][nx][2]: | |
new_shark[ny][nx] = (speed, i, size) | |
return new_shark | |
shark_size = 0 | |
for idx in range(c): | |
shark_size += get_shark(idx, maps) | |
maps = move_sharks(maps) | |
print(shark_size) |
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