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RSA - Given p,q and e.. recover and use private key w/ Extended Euclidean Algorithm - crypto150-what_is_this_encryption @ alexctf 2017
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#!/usr/bin/python | |
## RSA - Given p,q and e.. recover and use private key w/ Extended Euclidean Algorithm - crypto150-what_is_this_encryption @ alexctf 2017 | |
# @author intrd - http://dann.com.br/ (original script here: http://crypto.stackexchange.com/questions/19444/rsa-given-q-p-and-e) | |
# @license Creative Commons Attribution-ShareAlike 4.0 International License - http://creativecommons.org/licenses/by-sa/4.0/ | |
import binascii, base64 | |
p = 0xa6055ec186de51800ddd6fcbf0192384ff42d707a55f57af4fcfb0d1dc7bd97055e8275cd4b78ec63c5d592f567c66393a061324aa2e6a8d8fc2a910cbee1ed9 | |
q = 0xfa0f9463ea0a93b929c099320d31c277e0b0dbc65b189ed76124f5a1218f5d91fd0102a4c8de11f28be5e4d0ae91ab319f4537e97ed74bc663e972a4a9119307 | |
e = 0x6d1fdab4ce3217b3fc32c9ed480a31d067fd57d93a9ab52b472dc393ab7852fbcb11abbebfd6aaae8032db1316dc22d3f7c3d631e24df13ef23d3b381a1c3e04abcc745d402ee3a031ac2718fae63b240837b4f657f29ca4702da9af22a3a019d68904a969ddb01bcf941df70af042f4fae5cbeb9c2151b324f387e525094c41 | |
ct = 0x7fe1a4f743675d1987d25d38111fae0f78bbea6852cba5beda47db76d119a3efe24cb04b9449f53becd43b0b46e269826a983f832abb53b7a7e24a43ad15378344ed5c20f51e268186d24c76050c1e73647523bd5f91d9b6ad3e86bbf9126588b1dee21e6997372e36c3e74284734748891829665086e0dc523ed23c386bb520 | |
def egcd(a, b): | |
x,y, u,v = 0,1, 1,0 | |
while a != 0: | |
q, r = b//a, b%a | |
m, n = x-u*q, y-v*q | |
b,a, x,y, u,v = a,r, u,v, m,n | |
gcd = b | |
return gcd, x, y | |
n = p*q #product of primes | |
phi = (p-1)*(q-1) #modular multiplicative inverse | |
gcd, a, b = egcd(e, phi) #calling extended euclidean algorithm | |
d = a #a is decryption key | |
out = hex(d) | |
print("d_hex: " + str(out)); | |
print("n_dec: " + str(d)); | |
pt = pow(ct, d, n) | |
print("pt_dec: " + str(pt)) | |
out = hex(pt) | |
out = str(out[2:-1]) | |
print "flag" | |
print out.decode("hex") | |
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