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February 9, 2017 23:57
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Would it be possible for this type to be inferred?
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> :set -XGADTs -XDataKinds | |
> data Nat = Z | S Nat | |
> data Vect n a where { Nil :: Vect 'Z a; (:-) :: a -> Vect n a -> Vect ('S n) a } | |
> :t () :- Nil | |
() :- Nil :: Vect ('S 'Z) () | |
> :t \(a :- Nil) -> a | |
<interactive>:1:16: | |
Couldn't match expected type `r' with actual type `t1' | |
`r' is untouchable | |
inside the constraints (n ~ 'Z) | |
bound by a pattern with constructor | |
Nil :: forall a. Vect 'Z a, | |
in a lambda abstraction | |
at <interactive>:1:8-10 | |
`r' is a rigid type variable bound by | |
the inferred type of it :: Vect t t1 -> r at <interactive>:1:1 | |
`t1' is a rigid type variable bound by | |
the inferred type of it :: Vect t t1 -> r at <interactive>:1:1 | |
Possible fix: add a type signature for `it' | |
Relevant bindings include a :: t1 (bound at <interactive>:1:3) | |
In the expression: a | |
In the expression: \ (a :- Nil) -> a | |
> :t (\(a :- Nil) -> a) :: Vect ('S 'Z) a -> a | |
(\(a :- Nil) -> a) :: Vect ('S 'Z) a -> a :: Vect ('S 'Z) a -> a |
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