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August 17, 2016 23:34
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--- | |
title: "Babynames (Parameterized)" | |
author: "Chester Ismay" | |
date: "August 17, 2016" | |
output: | |
html_document: | |
toc: true | |
toc_float: true | |
code_folding: show | |
code_download: true | |
params: | |
name: Jack | |
year: 1990 | |
--- | |
```{r setup, include=FALSE, message=FALSE} | |
# This is where we load in all the packages we plan to use | |
# List of packages required for this analysis | |
pkg <- c("dplyr", "babynames") | |
# Check if packages are not installed and assign the | |
# names of the packages not installed to the variable new.pkg | |
new.pkg <- pkg[!(pkg %in% installed.packages())] | |
# If there are any packages in the list that aren't installed, | |
# install them | |
if (length(new.pkg)) { | |
install.packages(new.pkg, repos = "http://cran.rstudio.com") | |
} | |
# Load the packages into R | |
library(dplyr) | |
library(babynames) | |
data("babynames", package = "babynames") | |
``` | |
The `babynames` data comes from the Social Security Administration and gives information about the Top 1000 names given to children in the USA since 1880 (<http://www.ssa.gov/oact/babynames/limits.html>). Notice that the data is called `names` above when we load it from the `babynames` package, but you will receive an error if you try to use `names` as your data frame before the `%>%`. This is just a quirk with how Hadley labeled things. | |
## Problem | |
Identify how many people were born with **parameterized first name** (`r params$name`) in the US in **paramaterized year** (`r params$year`). | |
```{r example} | |
entered_name <- params$name | |
entered_year <- params$year | |
result <- babynames %>% filter(name == entered_name) %>% | |
filter(year == entered_year) %>% | |
summarize(count = sum(n)) | |
result | |
``` | |
## Update inline text | |
We can reference values stored in R directly in your text. | |
**Something like this:** | |
We have determined that (of the top 1000 names) in `r entered_year`, there were `r format(result, big.mark = ',')` babies born in the US with the first name '`r entered_name`'. | |
Additionally, we can produce output conditional on results using the `ifelse` function in R: | |
`r ifelse(result < 500, "The name you entered was not very popular in that year.", "")` | |
**One more tweak**: You can use the `paste0` function to create a sentence based on values. | |
`r ifelse(result < 500, paste0("The name '", entered_name, "' was not very popular in ", entered_year, "."), "What a popular name!")` | |
## Try this! | |
You'll need to `Run Current Chunk` here to get the desired output. | |
```{r try_this, eval = FALSE} | |
names_array <- c("Hayden", "Justin", "Doug", "Mary") | |
years_array <- rep(1950, times = length(names_array)) | |
rm(params) | |
for(i in 1:length(names_array)){ | |
rmarkdown::render("babynames_parameterized.Rmd", | |
params = list(name = names_array[i], year = years_array[i]), | |
output_dir = "results", | |
output_file = paste0(names_array[i], "_", years_array[i], ".html") | |
) | |
} | |
``` | |
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