Bracket Matching (find out if all the brackets in a string matches)

SearchingChallenge.js

/**
* A javascript solution Have the function SearchingChallenge(str) take the str parameter being passed and return 1 #ofBrackets if the brackets are correctly matched and each one is accounted for. Otherwise return 0. For example: if str is "(hello [world])(!)", then the output should be 1 3 because all the brackets are matched and there are 3 pairs of brackets, but if str is "((hello [world])" the the output should be 0 because the brackets do not correctly match up. Only "(", ")", "[", and "]" will be used as brackets. If str contains no brackets return 1.
**/

function SearchingChallenge(str) { 
   
  let bracketMaps = {
    '(': 0,
    '[': 0
  };

  let bracketPairs = 0;
  

  for(const char of str) {
    if(char === '(' || char === '[') {
      bracketMaps[char]++;
      bracketPairs++;
    }

    if(char === ')') {
      bracketMaps['(']--;
    }
    if(char === ']') {
      bracketMaps['[']--;
    }
  }

  const isMatched = (bracketMaps['('] === 0 || bracketMaps['[']) === 0;
  if(!isMatched) {
    return "0";
  }

  if(bracketPairs === 0) {
    return "1";
  }
  
  return `1 ${bracketPairs}`; 

}
   

console.log(SearchingChallenge(readline()));