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Created October 11, 2016 07:26
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BCINCSEQ SPOJ
// contest: http://www.spoj.com/PTIT/problems/BCINCSEQ/
// author : Nguyen Minh Tuan
// lang : C/C++
// algo : Dynamic Programming
#include <algorithm>
#include <functional>
#include <iostream>
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <sstream>
#include <string>
#include <vector>
#include <set>
#include <map>
#include <cmath>
#define _for(i,a,b) for(int i=(a),_b_=(b),_d_=(a<b?1:-1);i!=_b_;i+=_d_)
#define FOR(i,a,b) for(int i = a; i <= b; i++)
#define _it(i,v) for (typeof((v).begin()) i = (v).begin(); i != (v).end(); ++i)
#define _all(v) v.begin(), v.end()
#define DEBUG(x) { cout << #x << " = " << x << endl; }
#define sqr(x) ((x)*(x))
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
int main(){
ios_base::sync_with_stdio(0);
cin.tie(0);
// solution starts...
#ifndef ONLINE_JUDGE
freopen("INPUT.inp", "r", stdin);
#endif
int n, a[100005], dp[100005], ans=0;
cin >> n;
FOR(i,1,n) cin >> a[i];
a[0]=1000000000;
dp[0]=0;
FOR(i,1,n) {
if(a[i] >= a[i-1]) {
dp[i]=dp[i-1]+1;
} else {
dp[i]=1;
}
}
FOR(i,1,n) {
if(dp[i] > ans) ans=dp[i];
}
cout << ans << '\n';
// solution ends...
return 0;
}
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