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def gauss(A): | |
m = len(A) | |
assert all([len(row) == m + 1 for row in A[1:]]), "Matrix rows have non-uniform length" | |
n = m + 1 | |
for k in range(m): | |
pivots = [abs(A[i][k]) for i in range(k, m)] | |
i_max = pivots.index(max(pivots)) + k | |
# Check for singular matrix | |
assert A[i_max][k] != 0, "Matrix is singular!" | |
# Swap rows | |
A[k], A[i_max] = A[i_max], A[k] | |
for i in range(k + 1, m): | |
f = A[i][k] / A[k][k] | |
for j in range(k + 1, n): | |
A[i][j] -= A[k][j] * f | |
# Fill lower triangular matrix with zeros: | |
A[i][k] = 0 | |
# Solve equation Ax=b for an upper triangular matrix A | |
x = [] | |
for i in range(m - 1, -1, -1): | |
x.insert(0, A[i][m] / A[i][i]) | |
for k in range(i - 1, -1, -1): | |
A[k][m] -= A[k][i] * x[0] | |
return x |
def GaussElim(M,V): # Get a Matrix A and Vector B
import numpy as np
A=np.array(M)
B=np.array(V)
Adim=A.shape; # Dimension of A Matrix
Bdim=B.shape;
print(Adim,Bdim)
NumRow=Adim[0]
NumCol=Adim[1] # How many Number of Rows and Columns
Solve_x=np.zeros((NumRow,1));
# Check for Consistencey of the Solution
if NumRow==NumCol:
print("Number of Equation is Equal to Number of Variables:- Good \/Checked")
if Bdim[0]==NumRow:
print("Size of the Vector is Consistent with Number of Variables:-Good \/Checked")
# When no solution due to inconsistency
else:
print("Size of the Vector is Note Correct")
Solve_x="NaN"
b=B.reshape((NumRow,1)) # Reshaping the Vector B into b as a Column vector
# NumPy arrays by default row vector
# Joining A and b
CatAB_stack=np.hstack((A,b)) # Horizontally stacking or Concatinating
# the M and V
# or Use Numpy Concatenate command as follows
CatAB_concat=np.concatenate((A,b),axis=1);
#######################################################################
## Forward Elimination
# Getting the size of the new concatenated matrix
R=NumRow; # Getting Number of Rows - Redundant NumRow
C=CatAB_stack.shape[1]; # Getting Number of Columns (NumCol+1)
CatAB=CatAB_concat; # Initializig the CatAB - Continuously changing
# Forward Eliminated Matrix
# range defines like this range(Start Index, Max number of loop, interval)
for j in range(NumRow-1): # for j running from 0 to NumRow-2
for i in range(j+1, NumRow): # for i running from j+1 to NumRow
CatAB[i,j:C]=CatAB[i,j:C]-(CatAB[j,j:C]*(CatAB[i,j]/CatAB[j,j]));
#######################################################################
## Backward Substitution
Solve_x=np.zeros((R,1)) # Initializing the solution vector
Solve_x[R-1]=CatAB[R-1,C-1]/CatAB[R-1,R-1]; # Solve the last variable -1 to satisfy the index "Matlab-1=C"
# Reverse Looping range(Starting Number,Last Number,- negative increment)
for i in range(NumRow-1,-1,-1):
var=0
for j in range(i+1, C-1):
var+=CatAB[i,j]*Solve_x[j]
Solve_x[i]=(CatAB[i,C-1]-var)/CatAB[i,i]
return [Solve_x,CatAB]
hi , thank you for code but I could not do this which is for 4 or more unknown equations . could you help me ?
Haven't touched this in ages, can you provide a working example? This has handled arbitrary sized equations.
Thanks for the code. I am having trouble with singular matrices when using it with bigger matrices and have found the following article which deals with this specific problem for gaussian elimination. It seems to be an easy extension, I wonder if you could give help me with it given I am not familiar with the method: "When a row of zeros, say the ith, is encountered in the transform of A, the diagonal element of that row is changed to 1, and in the augmented portion of the matrix all other rows are changed to 0, the ith row being unchanged".
how would i write a program that does forward elimination - use the naive method for python code
Haven't touched this in ages, can you provide a working example? This has handled arbitrary sized equations.