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how-to-filter-array-of-object-has-array-of-objects.js

var data = [{
  id: 7485,
  name: "Klädseltvätt",
  categories: [{
    id: 189,
    name: "Tjänster",
    slug: "services"
  }, {
    id: 207,
    name: "Rekond",
    slug: "rekond"
  }]
}, {
  id: 7456,
  name: "Hankook Kinergy Eco 2 K435 185/60-14 H",
  categories: [{
    id: 28,
    name: "Sommardäck",
    slug: "sommardack"
  }]
}]


let computed = data.filter((group) => {
  let _name
  let _group = []
  let _temp

  if(group.categories.map((item)=>{
    _name = item.name
    _temp = group.name
    debugger
    _group.push(group)
    return item
  }).length>0){
    group.name = _name
    group.products = _group
    return group
    debugger
  }
})
console.log(computed)

function groupByCategory(arr) {
	let res = {};
	let categories = [];
	arr.forEach(el => {
		el.categories.forEach(c => {
			// Skapa ny kategori om inte redan existerar
			if (!categories.includes(c.slug)) {
				categories.push({
					name: c.name,
					slug: c.slug,
					products: [el]
				});
			} else {
				// Lägg till produkt i existerande kategori
				categories.forEach(_c => {
					if (_c.slug === c.slug) {
						_c.products.push(el)
					}
				})
			}
		});
	});

	return categories;
}

function (products) => {
  // reduce down each product into a category map
  // reducera varje produkt till en kategori.Map()
  const productsGroupedByCategory = products.reduce((categories, product) => {
    // insert the current product into each of the categories it contains
    product.categories.forEach(category => {
      // if the category exists in the map, we just need to append the current product
      if (category.id in categories)
        categories[category.id].products.push(product)
      else // otherwise, create a new category object with the current product
      categories[category.id] = ({ ...category, products: [product] })
    })
    return categories
  }, ({}))

  // convert the object into an array of objects
  return Object.values(productsGroupedByCategory)
}