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Last active January 13, 2025 12:00
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jacksleight commented Jan 10, 2025 •
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I have a rectangle that is 440 wide and 320 high.

I create a 30 degree isometric projection with the rectangle on both the XY and XZ planes.

I now want to calculate the width and height of the visual bounding boxes around the XY and XZ planes of the projection.

I already have three of the four formulas:

xy-plane-width  = (width * sin(pi / 4)) + (height * cos(pi / 4))
xy-plane-height = xy-plane-width * tan(angle)
xz-plane-width  = width * sin(pi / 4)
xz-plane-height = ?

However I can't figure out the formula for the XZ plane height.

The dimensions and angle here are just examples, I need the formulas as the actual width, height and angle will change.

Here's an illustration of the problem if that helps explain further:

measurements

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