Solution for WKInterface button doesn't change title

PresentedViewController.m

/* Catch and use the model object*/

@interface PresentedViewController()

@property (nonatomic, strong) SGYourActionModelObject *actionBlockObject;

@end

- (void)awakeWithContext:(id)context {
  NSAssert([context isKindOfClass:[SGYourActionModelObject class]], @"Expected SGYourActionModelObject")
  
  self.actionBlockObject = context;
}

- (void)someMethodThatYouWantToDoSomething {
//Something something something
[self popController];
self.actionBlockObject.actionBlock(); //BA BOOM!
}

PresentingViewController.m

/* Set up the model object… */

//… Code 

- (id)contextForSegueWithIdentifier:(NSString *)segueIdentifier {
  if ([segueIdentifier isEqualToString:@"AwesomeSegue"]) {
  typeof(self) __weak weakSelf = self;
  YourActionBlock actionBlock = ^(){
    //Do whatever want. Use weakSelf.
    //In your case, you'd change the title of the button.
  };
  return [[SGYourActionModelObject alloc] initWithActionBlock:actionBlock]; //This gets pass to the presented view controller
}

SGYourActionModelObject.h

#import <Foundation/Foundation.h>
#import <WatchKit/WatchKit.h>

typedef void (^YourActionBlock) (/*You could place an object in here*/);

@interface SGYourActionModelObject : NSObject

@property (nonatomic, strong, readonly) YourActionBlock actionBlock;

- (instancetype)initWithActionBlock:(YourActionBlock)actionBlock;

@end

SGYourActionModelObject.m

#import "SGYourActionModelObject.h"

@interface SGYourActionModelObject ()

@property (nonatomic, strong) YourActionBlock actionBlock;


@end

@implementation SGYourActionModelObject

- (instancetype)initWithActionBlock:(YourActionBlock)actionBlock {
    self = [super init];
    if (self) {
        _yourActionBlock = actionBlock;
    }
    return self;
}

@end

Thank you so much.