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April 25, 2019 22:24
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Solution for https://codeforces.com/contest/1152/problem/C
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#include <bits/stdc++.h> | |
using namespace std; | |
using ll = long long; | |
constexpr ll p = 1000000007; | |
ll gcd(ll a, ll b) { | |
while(b) { | |
ll tmp = b; | |
b = a % b; | |
a = tmp; | |
} | |
return a; | |
} | |
ll lcm(ll a, ll b) { | |
return a * b / gcd(a, b); | |
} | |
ll fast_pow(ll base, ll pow, ll mod) { | |
base %= mod; | |
if(base == 0) return 0ll; | |
ll ret = 1ll; | |
while(pow) { | |
if(pow & 1ll == 1ll) ret = (ret * base) % mod; | |
base = (base * base) % mod; | |
pow >>= 1; | |
} | |
return ret; | |
} | |
bool miller_rabin_test(ll n, ll precision=10) { | |
if(n == 1) return false; | |
if(n & 1ll == 0) return n == 2; | |
if(n == 3 || n == 5 || n == 7) return true; | |
random_device seed; | |
mt19937 gen(seed()); | |
uniform_int_distribution<ll> randll(2, n - 2); | |
ll s = 0, d = n - 1; | |
while(d & 1ll == 0) { | |
s++; | |
d >>= 1; | |
} | |
while(precision--) { | |
ll a = randll(gen); | |
ll x = fast_pow(a, d, n); | |
if(x == 1 || x == n - 1) continue; | |
bool a_good = false; | |
for (int i = 0; i < s - 1; ++i) { | |
x = (x * x) % n; | |
if(x == 1) return false; | |
else if(x == n - 1) { | |
a_good = true; | |
break; | |
} | |
} | |
if(!a_good) return false; | |
} | |
return true; | |
} | |
vector<ll> get_primes(ll n) { | |
vector<ll> ret, lp(n + 1, 0); | |
for (int i = 2; i <= n; ++i) { | |
if(lp[i] == 0) { | |
lp[i] = i; | |
ret.emplace_back(i); | |
} | |
for(int j = 0; j < ret.size() && ret[j] < lp[i] && i * ret[j] <= n; j++) { | |
lp[i * ret[j]] = ret[j]; | |
} | |
} | |
return ret; | |
} | |
vector<pair<ll, ll>> get_factors(ll n) { | |
vector<ll> primes = get_primes(100000); | |
vector<pair<ll, ll>> ret; | |
for(const auto &prime : primes) { | |
if(n % prime != 0) continue; | |
ll count = 0; | |
while(n % prime == 0) { | |
count++; | |
n /= prime; | |
} | |
ret.emplace_back(prime, count); | |
if(n == 1) break; | |
} | |
if(miller_rabin_test(n)) { | |
ret.emplace_back(n, 1); | |
} | |
return ret; | |
} | |
void _rec_divisors(ll val, ll index, const vector<ll> &base, const vector<ll> &exp, vector<ll> &coll) { | |
if(index == base.size()) { | |
coll.emplace_back(val); | |
return; | |
} | |
ll curr = 1ll; | |
for (int i = 0; i <= exp[index]; ++i) { | |
_rec_divisors(val * curr, index + 1, base, exp, coll); | |
curr *= base[index]; | |
} | |
} | |
vector<ll> get_divisors(ll n) { | |
if(n == 1) return vector<ll>(1, 1); | |
auto factors = get_factors(n); | |
ll l = factors.size(); | |
vector<ll> ret, base(l), exp(l); | |
for (int i = 0; i < l; ++i) { | |
base[i] = factors[i].first; | |
exp[i] = factors[i].second; | |
} | |
_rec_divisors(1ll, 0ll, base, exp, ret); | |
return ret; | |
} | |
int main() { | |
ll a, b; | |
cin >> a >> b; | |
if(a > b) swap(a, b); | |
ll bk = 0, blcm = lcm(a, b), k = 1; | |
if(b - a == 0) { | |
cout << 0 << endl; | |
return 0; | |
} | |
vector<ll> divisors = get_divisors(b - a); | |
for(const auto &div : divisors) { | |
k = div - a % div; | |
ll clcm = lcm(a + k, b + k); | |
if(clcm < blcm || clcm == blcm && k < bk) { | |
blcm = clcm; | |
bk = k; | |
} | |
} | |
cout << bk << endl; | |
return 0; | |
} |
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