Created
December 4, 2011 16:14
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Euler 32
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| # first we'll need a set to store results in- that means we won't need to de-dupe | |
| h=set() | |
| total=0; | |
| # now, we'lll make the strings- | |
| # 1 digits x 4 digits will be 4 or 5 digits (9-10 total) and 2 digits x 3 digits will by 4 or 5 digits (9-10 total) so try up to 9999x99 | |
| for a in range(1,9999): | |
| for b in range(1,99): | |
| product = str(a)+"x"+str(b)+"x"+str(a*b) | |
| # now we'll evaluate each string to see if it meets our criteria | |
| # first make sure there are only 9 numbers (plus two x's =11) | |
| if (len(product)==11): | |
| l=[] | |
| total = 0 | |
| for i in range (0,len(product)): | |
| if ((product[i:i+1]) != "x"): | |
| l.append(int(product[i:i+1])) | |
| l.sort() | |
| if (l[0]==1 and l[1]==2 and l[2]==3 and l[3]==4 and l[4]==5 and l[5]==6 and l[6]==7 and l[7]==8 and l[8]==9): | |
| print product | |
| h.add(a*b) | |
| print sum(h) |
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