Created
December 8, 2011 20:50
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euler 43 python
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| # let's try using the built in permutation function! | |
| import itertools | |
| x = itertools.permutations('0123456789', 10) | |
| sum = 0 | |
| for i in x: | |
| string= "".join(list(i)) | |
| number = int(string) | |
| # you can add a number of these if requirements using divisibility rules- i picked the obvious three | |
| if (number > 1000000000 and int(i[3])%2==0 and int(i[5])%5==0): | |
| if (int(i[1]+i[2]+i[3])%2==0 and int(i[2]+i[3]+i[4])%3==0 and int(i[3]+i[4]+i[5])%5==0 and int(i[4]+i[5]+i[6])%7==0 and int(i[5]+i[6]+i[7])%11==0 and int(i[6]+i[7]+i[8])%13==0 and int(i[7]+i[8]+i[9])%17==0): | |
| sum = sum + number | |
| print "sum is",sum |
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