gistfile1.txt

# let's start by making a set of all pentagonal numbers from to n=10000 
# you can actually do to like n=4000 and get the same answer
# then let's say check every number in set vs. every other.  
# if sum and difference is also in the set, compute the difference, print

h = set()

for i in range (1,10000):
	pent = (i*(3*i-1))/2
	h.add(pent)

min_d=0

for i in h:
	for j in h:
		if i+j in h:
			if i-j in h:
				print i,j,j-i