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December 10, 2011 19:35
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Euler 49 Prime Permutations
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| # http://projecteuler.net/problem=49 | |
| # we'll use the python built-in permutation function | |
| import itertools | |
| # prime sieve | |
| n=100000 | |
| myPrimes = [True]*(n+1) | |
| for i in range (2,n): | |
| if myPrimes[i] == True: | |
| j = 2*i | |
| while j<=n: | |
| myPrimes[j]=False | |
| j=j+i | |
| # for each k, see if b and c are in the set of prime permutations | |
| for k in range (1488,9999): | |
| if myPrimes[k] == True: | |
| b = k + 3330 | |
| c = k + 6660 | |
| perms = itertools.permutations(str(k), 4) | |
| my_set = set() | |
| for l in perms: | |
| number=int("".join(list(l))) | |
| if number>1000 and myPrimes[number]: | |
| my_set.add(number) | |
| if b in my_set and c in my_set: | |
| print "set is",k,b,c | |
| print "string is",str(k)+str(b)+str(c) |
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