Created
December 24, 2011 02:07
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Euler 70- a bit slow
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| factors = [1]*10000001 | |
| for i in range (0,len(factors)): | |
| factors[i]=i | |
| # set up prime sieve to n | |
| n=10000000 | |
| myPrimes = [True]*(n+1) | |
| last = 0 | |
| for i in range (2,n): | |
| if myPrimes[i] == True: | |
| j = 2*i | |
| while j<=n: | |
| myPrimes[j]=False | |
| factors[j]=factors[j]*(1.0-(1.0/i)) | |
| j=j+i | |
| min_ratio = 10 | |
| min_n = 0 | |
| for n in range (8000000,10000000): | |
| if myPrimes[n]!=True: | |
| if len(str(int(factors[n]))) == len(str(n)): | |
| testa = [] | |
| for p in range (0,len(str(int(factors[n])))): | |
| testa.append(str(int(factors[n]))[p:p+1]) | |
| testa.sort() | |
| testb = [] | |
| for q in range (0,len(str(n))): | |
| testb.append(str(n)[q:q+1]) | |
| testb.sort() | |
| if testa == testb: | |
| # print n,factors[n],n/factors[n] | |
| if n/factors[n] < min_ratio: | |
| min_ratio = n/factors[n] | |
| min_n=n | |
| print min_n,min_ratio |
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