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def window(seq, n=2): | |
"Returns a sliding window (of width n) over data from the iterable" | |
" s -> (s0,s1,...s[n-1]), (s1,s2,...,sn), ... " | |
it = iter(seq) | |
result = tuple(islice(it, n)) | |
if len(result) == n: | |
yield result | |
for elem in it: | |
result = result[1:] + (elem,) | |
yield result | |
def lock_is_open(combo, tumbler): | |
"Check if the tumbler contains the combination based on" | |
"a simple combination lock algorithm" | |
# grab the last number | |
final = tumbler[-1] | |
# cut the list down to only the numbers that are "edges", | |
# i.e. numbers where the lock changed direction | |
# | |
# on a traditional lock, you enter the combination and then | |
# attempt to open the lock to see if the final digit is correct. | |
# since there is no explicit “open” command in this case, tack | |
# on the final number (which represents the current setting of | |
# the Nest) before checking to see if we have a match. | |
check = [x[1] for x in window(tumbler,3) if max(x) == x[1] or min(x) == x[1]] + [final] | |
# convert the list to check into windows of len(combo) size | |
# this allows us to use a simple "in" operator to check if the combo | |
# is inside the list | |
check = [x for x in window(check,len(combo))] | |
# is the combo present in the tumbler? | |
return (tuple(combo) in check) |
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