Created
May 7, 2013 11:20
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A* Algorithm implementation in python.
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# Enter your code here. Read input from STDIN. Print output to STDOUT | |
class Node: | |
def __init__(self,value,point): | |
self.value = value | |
self.point = point | |
self.parent = None | |
self.H = 0 | |
self.G = 0 | |
def move_cost(self,other): | |
return 0 if self.value == '.' else 1 | |
def children(point,grid): | |
x,y = point.point | |
links = [grid[d[0]][d[1]] for d in [(x-1, y),(x,y - 1),(x,y + 1),(x+1,y)]] | |
return [link for link in links if link.value != '%'] | |
def manhattan(point,point2): | |
return abs(point.point[0] - point2.point[0]) + abs(point.point[1]-point2.point[0]) | |
def aStar(start, goal, grid): | |
#The open and closed sets | |
openset = set() | |
closedset = set() | |
#Current point is the starting point | |
current = start | |
#Add the starting point to the open set | |
openset.add(current) | |
#While the open set is not empty | |
while openset: | |
#Find the item in the open set with the lowest G + H score | |
current = min(openset, key=lambda o:o.G + o.H) | |
#If it is the item we want, retrace the path and return it | |
if current == goal: | |
path = [] | |
while current.parent: | |
path.append(current) | |
current = current.parent | |
path.append(current) | |
return path[::-1] | |
#Remove the item from the open set | |
openset.remove(current) | |
#Add it to the closed set | |
closedset.add(current) | |
#Loop through the node's children/siblings | |
for node in children(current,grid): | |
#If it is already in the closed set, skip it | |
if node in closedset: | |
continue | |
#Otherwise if it is already in the open set | |
if node in openset: | |
#Check if we beat the G score | |
new_g = current.G + current.move_cost(node) | |
if node.G > new_g: | |
#If so, update the node to have a new parent | |
node.G = new_g | |
node.parent = current | |
else: | |
#If it isn't in the open set, calculate the G and H score for the node | |
node.G = current.G + current.move_cost(node) | |
node.H = manhattan(node, goal) | |
#Set the parent to our current item | |
node.parent = current | |
#Add it to the set | |
openset.add(node) | |
#Throw an exception if there is no path | |
raise ValueError('No Path Found') | |
def next_move(pacman,food,grid): | |
#Convert all the points to instances of Node | |
for x in xrange(len(grid)): | |
for y in xrange(len(grid[x])): | |
grid[x][y] = Node(grid[x][y],(x,y)) | |
#Get the path | |
path = aStar(grid[pacman[0]][pacman[1]],grid[food[0]][food[1]],grid) | |
#Output the path | |
print len(path) - 1 | |
for node in path: | |
x, y = node.point | |
print x, y | |
pacman_x, pacman_y = [ int(i) for i in raw_input().strip().split() ] | |
food_x, food_y = [ int(i) for i in raw_input().strip().split() ] | |
x,y = [ int(i) for i in raw_input().strip().split() ] | |
grid = [] | |
for i in xrange(0, x): | |
grid.append(list(raw_input().strip())) | |
next_move((pacman_x, pacman_y),(food_x, food_y), grid) |
Why the aStar function is calling four times in next_move function?
If you are referring to my version, not the author's one, the answer I should give you is: my bad. I can't remember what I was trying to do at the time, maybe I just clicked the ctrl+v shortcut a few times by mistake. I just can't see a reason for executing 4 times the same thing.
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The reason of why I want to see your code is because you might have modified something, even if just a line or a variable, and it might have some impact over the full code. After all, as the old ones said: "In my PC at home the code works, not sure why on yours it doesn't".