Find object in list of objects or return None

find_object_in_list.py

next((x for x in test_list if x.value == value), None)
'''
This gets the first item from the list that matches the condition, and returns None if no item matches. It's my preferred single-expression form.

However,
'''
for x in test_list:
    if x.value == value:
        print "i found it!"
        break
'''
The naive loop-break version, is perfectly Pythonic -- it's concise, clear, and efficient. To make it match the behavior of the one-liner:

'''
for x in test_list:
    if x.value == value:
        print "i found it!"
        break
else:
    x = None
'''
This will assign None to x if you don't break out of the loop.

Source: <http://stackoverflow.com/questions/7125467/find-object-in-list-that-has-attribute-equal-to-some-value-that-meets-any-condi>
'''