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// 顺延函数:如果上一个动作完成,则当前动作替换上一个 | |
function shift(fn, time) { | |
time = time || 50; | |
var queue = this._shift_fn, current; | |
queue ? queue.concat([fn, time]) : (queue = [[fn, time]]); | |
current = queue.pop(); | |
clearTimeout(this._shift_timeout); | |
this._shift_timeout = setTimeout(function() { | |
current[0](); | |
}, current[1]); | |
} | |
// 测试函数 | |
function fn1() { | |
console.log('fn1'); | |
} | |
function fn2() { | |
console.log('fn2'); | |
} | |
function fn3() { | |
console.log('fn3'); | |
} | |
// 最终因为 fn1 在 fn2 执行的时候还没完成,fn1 不执行,fn2 执行,fn3 在 fn2 执行后再执行,同样获得结果 | |
shift(fn1, 10); | |
shift(fn2, 10); | |
setTimeout(function() { | |
shift(fn3); | |
}, 10); |
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