Special triplets

triplets.py

#   ///////////////////////////////////////
#  ------------Find the Triplets---------
# //////////////////////////////////////

'''
Question : You are given an array of integer values and a interger value (suppose x).
           You have to return number of triplets found in the given array such that
           2nd element = 1st element + x
           3rd element = 2nd element + x
    
    Example = we are given ( [1,2,3,6,7,8] , 1 )

    Our answer (2) 
    Because ([1,2,3] , [6,7,8])
'''

def helper(array, x,d):
    for i in range(2):
        temp = x + d
        if temp not in array:
            return False
        x = temp
    return True


def triple(array,d):
    answer = 0
    for i in array:
        if helper(array,i,d):
            answer += 1
    return answer

print(triple([1,2,3,5,6,7,9,10,11],1))