Check double according to the rules

check-double.py

# Write a python function, check_double(number) which accepts a whole number and returns True if it satisfies the given conditions.

# 1. The number and its double should have exactly the same number of digits.
# 2. Both the numbers should have the same digits ,but in different order.
# Otherwise it should return False.

# convert number to  list
#O(n)
def numToList(number):
    l_st = []
    while(number):
        l_st.append(number%10);
        number //= 10;
    return l_st;

#checking no digits is at same place in both numbers
#O(n)
def samePlace(num, dou):
    i = len(num) -1
    while(i):
        if num[i] == dou[i]:
            return True
        i-=1;
    return False

#checking both have same digits
#O(nlogn) 
def sameDigits(num,dou):
    num = sorted(num)
    dou = sorted(dou)
    
    if (num != dou):
        return False
    return True

# check_double
#O(nlogn)
def check_double(number):
    double = number*2
    
    if number == double:
        return False
    
    num = numToList(number)
    dou = numToList(double)
    if (not samePlace(num,dou) and sameDigits(num,dou)):
        return True
    return False

# main    
if __name__ == "__main__":
    print(check_double(125874))

if temp[i] == numb:
count += 1
can u explain this part

if temp[i] == numb:
count += 1
can u explain this part

I don't remember what i did 2 years back, but i guess i missed i+=1, i guess i was checking no digit have same place.
Anyway i have updated the code. Now it will be easy to understand.

i don't how you writing a code but suggest me a good way to become a coder like you.