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May 16, 2021 08:51
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Square Root | C++ | Long Division Method
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//This only take int data type and input. | |
//More inprovment can be done, example in helper we can use binary search. | |
#include <iostream> | |
#include <vector> | |
std::vector<int> getPairs(int num) | |
{ | |
std::vector<int> pairs; | |
while(num){ | |
int temp=0; | |
temp += num%100; | |
num /= 100; | |
pairs.insert(pairs.begin(),temp); | |
} | |
return pairs; | |
} | |
void helper(int& divident, int& divisor, int& mid_term, int& sqrt) | |
{ | |
for(auto j=1;j<=10;j++){ | |
int temp_divisor = divisor + j; | |
mid_term = temp_divisor*j; | |
if(mid_term > divident){ | |
mid_term = (temp_divisor-1) * (j -1); | |
sqrt = sqrt*10+j-1; | |
divisor = temp_divisor + j -2; | |
break; | |
} | |
else if(mid_term == divident){ | |
divisor = temp_divisor+j; | |
sqrt = sqrt*10 +j; | |
break; | |
} | |
} | |
} | |
int squareRoot(int num) | |
{ | |
std::vector<int> pairs = getPairs(num); | |
int sqrt = 0; | |
int divisor = 0; | |
int divident = 0; | |
for(auto i=0;i<pairs.size();i++){ | |
divident += pairs[i]; | |
int mid_term = 0 ; | |
helper(divident,divisor,mid_term,sqrt); | |
//std::cout << divisor <<" " << divident<<" "<<mid_term <<'\n'; | |
divisor *=10; | |
divident = (divident-mid_term)*100; | |
} | |
return sqrt; | |
} | |
int main() | |
{ | |
int t=0; | |
std::cin >> t; | |
while(t--){ | |
int num=0; | |
std::cin >> num; | |
std::cout << squareRoot(num) << '\n'; | |
} | |
} |
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