Created
June 28, 2015 16:19
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Hi, I was trying this but it doesn't work with some combinations ... so I came up with this variation: (I multiply the major version by 1000 to cater for having minor versions that go beyond 9 )
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function minVersion(version) { | |
//console.log('minVersion:: testing for jquery minimum of ' + version ); | |
if(typeof window.jQuery == 'undefined'){ | |
console.log('minVersion:: no jquery found ...'); | |
return false; | |
} | |
var vrs = window.jQuery.fn.jquery.split('.'), | |
min = version.split('.'); | |
//pad the arrays to 3 digits | |
while(vrs.length < 3) | |
vrs.push(0); | |
while(min.length < 3) | |
min.push(0); | |
//build a number | |
var req = parseInt(min[0])*1000 + parseInt(min[1])*10 + parseInt(min[2]); | |
var ins = parseInt(vrs[0])*1000 + parseInt(vrs[1])*10 + parseInt(vrs[2]); | |
return ins >= req; | |
} |
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