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@javamultiplex
Created September 20, 2017 12:05
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Octal to Binary Converter
package com.javamultiplex.baseconversion;
import java.util.Scanner;
/**
*
* @author Rohit Agarwal
* @category Base Conversion
* @problem Convert Octal to Binary
*
*/
public class OctalToBinary {
public static void main(String[] args) {
Scanner input = null;
try {
input = new Scanner(System.in);
System.out.println("Enter octal number : ");
String number = input.next();
if (isOctalNumber(number)) {
String binary = getBinaryFromOctalNumber(number);
System.out.println("Binary Number : " + binary);
} else {
System.out.println("Please enter valid octal number.");
}
} finally {
if (input != null) {
input.close();
}
}
}
private static String getBinaryFromOctalNumber(String number) {
// Convert Octal to Decimal
int decimal = getDecimalFromOctalNumber(number);
// Convert Decimal to Binary
String binary = getBinaryFromDecimalNumber(decimal);
return binary;
}
private static String getBinaryFromDecimalNumber(int decimal) {
int remainder = 0;
StringBuilder binary = new StringBuilder();
while (decimal != 0) {
remainder = decimal % 2;
// Converting Integer to String and adding into StringBuilder.
binary.append(String.valueOf(remainder));
decimal = decimal / 2;
}
// Reverse String using library function of StringBuilder class.
return binary.reverse().toString();
}
private static int getDecimalFromOctalNumber(String number) {
// Converting String to StringBuilder.
StringBuilder string = new StringBuilder(number);
string = string.reverse();
int length = string.length();
int digit, power, sum = 0;
for (int i = 0; i < length; i++) {
digit = string.charAt(i) - 48;
power = (int) Math.pow(8, i);
sum = sum + digit * power;
}
return sum;
}
private static boolean isOctalNumber(String number) {
/*
* Regular expression that matches string containing only octal
* digits[0-7].
*/
String pattern = "^[0-7]+$";
boolean result = false;
if (number.matches(pattern)) {
result = true;
}
return result;
}
}
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