Created
September 23, 2015 19:14
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Operator insertion
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| def f(digits, target, current=None, rest=None): | |
| """ | |
| It doesnt work for the given case, it does for small runs | |
| Some performance situation... | |
| The idea is to try each digit with each of the operators | |
| once the digit have been used, it will be appended to the current | |
| and a new iteration will be done with the other digits. | |
| It's important to notice that each digit will be tried recursively and exhaustively with every operator | |
| """ | |
| if not digits: | |
| return | |
| if not current and not rest: | |
| current = "" | |
| rest = digits | |
| if not rest: | |
| return | |
| operators = ['+', '-', '*', '/'] | |
| index = 1 | |
| for digit in rest: | |
| temp_current = current | |
| temp_rest = rest[index:] | |
| if temp_rest: | |
| for operator in operators: | |
| current += digit + " " + operator | |
| expression = current + temp_rest | |
| if eval(expression) == target: | |
| print expression | |
| f(digits, target, current, temp_rest) | |
| current = temp_current | |
| current = temp_current + digit | |
| index += 1 | |
| f("1234",5) |
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