FizzBuzz Python Solution

FizzBuzz.py

def fizzbuzz(n):

    if n % 3 == 0 and n % 5 == 0:
        return 'FizzBuzz'
    elif n % 3 == 0:
        return 'Fizz'
    elif n % 5 == 0:
        return 'Buzz'
    else:
        return str(n)

print "\n".join(fizzbuzz(n) for n in xrange(1, 21))

for n in range(1, 101):
    if not n % 3 and not n % 5:
        print('FizzBuzz')
    elif not n % 3:
        print('Fizz')
    elif not n % 5:
        print('Buzz')
    else:
        print(n)

In 480 bits (60 bytes) or 60 chars:

for i in range(100):print(i%3//2*'Fizz'+i%5//4*'Buzz'or i+1)

def fizzBuzz(n):
# Write your code here
for i in range(1, n + 1):
if i % 5 == 0 and i % 5 == 0:
print("FizzBuzz")
elif i % 3 == 0:
print("Fizz")
elif i % 5 == 0:
print("Buzz")
elif i % 3 != 0 or i % 5 != 0:
print(str(i))

Proof, code at work

def fizzBuzz():
stack = range(1, 100, 1)
for item in stack:
if item % 3 == 0 and item % 5 == 0:
item = "FizzBuzz"
elif item % 3 == 0:
item = "Fizz"
elif item % 5 == 0:
item = "Buzz"

    print(item)

fizzBuzz()