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Print a sqlite database file as YAML
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#!/usr/bin/env python2 | |
import argparse | |
import sys | |
import sqlalchemy | |
import yaml | |
def sqlite2yaml(filename): | |
engine = sqlalchemy.create_engine('sqlite:///{}'.format(filename)) | |
metadata = sqlalchemy.MetaData(bind=engine) | |
metadata.reflect() | |
tables = {} | |
for table in engine.table_names(): | |
columns = map(str, metadata.tables[table].columns.keys()) | |
rows = engine.execute('select * from {}'.format(table)).fetchall() | |
tables[table] = [] | |
for row in rows: | |
tables[table].append(dict(zip(columns, row))) | |
yaml.safe_dump(tables, sys.stdout, indent=4, default_flow_style=False) | |
def main(argv=sys.argv[1:]): | |
parser = argparse.ArgumentParser() | |
parser.add_argument('file') | |
args = parser.parse_args(argv) | |
sqlite2yaml(args.file) | |
if __name__ == "__main__": | |
main() |
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