Generate a random lowercase string with at least one number

gistfile1.py

python -c "import random; x = [random.choice('23456789') for x in range(1)] + [ random.choice('abcdefghjkmnpqrstwxyz') for x in range(3)]; random.shuffle(x); print ''.join(x)"

I still need to figure out how to only generate one number and randomise it's position....

python -c"".join(('abcdefghjkmnpqrstqxyz'*12)[ord(x)][0]+('23456789'*50)[ord(x)][0] for x in __import__('os').urandom(2))"

(Note the 'u' is gone too, forgot to mention that character can be dropped)

Jan, it's not easy to see how you are not generating the numeric zero / 1, are you starting the numeric index from > 1? I'm intrigued :)

chr 50 == 2 + [0..7](rand 8). I don't know that we need full readability on this, and the no-external modules perl solution seems fine as it fills all the criteria, even randomizing the digit. I need 1..4 to get 4 chars though. Jan - is that a buglet?

@jeff-hobbs: Yes, my latest entry should have 1..4 in it. And dropping the 'u' saves another character:

perl -e'@_=map substr(abcdefghjkmnpqrstwxyz,rand 21,1),1..4;splice@_,rand@_,1,chr 50+rand 8;print @_'

Finally, I would like to change @_ to @$ as a hidden reference to ActiveState (@$ is ActiveState similar to how *$ is Starbucks):

perl -e'@$=map substr(abcdefghjkmnpqrstwxyz,rand 21,1),1..4;splice@$,rand@$,1,chr 50+rand 8;print @$'