Created
November 30, 2020 18:13
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#buggy code took 20 minutes | |
class Solution: | |
def validateBinaryTreeNodes( | |
self, n: int, leftChild: List[int], rightChild: List[int] | |
) -> bool: | |
nparent = [0] * n | |
for i in range(n): | |
leftv = nparent[leftChild[i]] | |
if leftv != -1: | |
nparent[leftv] += 1 | |
rightv = nparent[rightChild[i]] | |
if rightv != -1: | |
nparent[rightv] += 1 | |
count = 0 | |
for v in nparent: | |
if v>1: | |
return False | |
if v == 0: | |
count += 1 | |
if count!=1: | |
return False | |
# find cycles | |
# return true if find cycle | |
def dfs(v,visited): | |
visited[v]=1 | |
for node in (leftChild[v],rightChild[v]): | |
if node!=-1: | |
if visited[node]==0: | |
if dfs(node,visited): | |
return True | |
if visited[node]==1: | |
return True | |
visited[v]=2 | |
return False | |
visited=[0]*n | |
for i in range(n): | |
if visited[i]==0: | |
if dfs(i,visited): | |
return False | |
return True | |
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