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List data size of objects in R
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## Credit: Taken from: http://stackoverflow.com/questions/1358003/tricks-to-manage-the-available-memory-in-an-r-session | |
# improved list of objects | |
.ls.objects <- function (pos = 1, pattern, order.by, | |
decreasing=FALSE, head=FALSE, n=5) { | |
napply <- function(names, fn) sapply(names, function(x) | |
fn(get(x, pos = pos))) | |
names <- ls(pos = pos, pattern = pattern) | |
obj.class <- napply(names, function(x) as.character(class(x))[1]) | |
obj.mode <- napply(names, mode) | |
obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class) | |
obj.prettysize <- napply(names, function(x) { | |
capture.output(print(object.size(x), units = "auto")) }) | |
obj.size <- napply(names, object.size) | |
obj.dim <- t(napply(names, function(x) | |
as.numeric(dim(x))[1:2])) | |
vec <- is.na(obj.dim)[, 1] & (obj.type != "function") | |
obj.dim[vec, 1] <- napply(names, length)[vec] | |
out <- data.frame(obj.type, obj.size, obj.prettysize, obj.dim) | |
names(out) <- c("Type", "Size", "PrettySize", "Rows", "Columns") | |
if (!missing(order.by)) | |
out <- out[order(out[[order.by]], decreasing=decreasing), ] | |
if (head) | |
out <- head(out, n) | |
out | |
} | |
# shorthand | |
lsos <- function(..., n=10) { | |
.ls.objects(..., order.by="Size", decreasing=TRUE, head=TRUE, n=n) | |
} | |
lsos() |
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