-
-
Save jeffsaracco/2572386 to your computer and use it in GitHub Desktop.
Convert in less than 30 lines
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Question: Convert following into the latter data structure in less than 30 lines: | |
List: | |
A, B, C | |
A, C, E | |
E, F, D | |
D, A, J | |
E, D, J | |
List | |
A, B, 1 (frequency) | |
A, C, 2 | |
A, D, 1 | |
A, E, 1 | |
A, J, 1 | |
B, C, 1 | |
C, E, 1 | |
D, E, 2 | |
D, F, 1 | |
D, J, 2 | |
E, F, 1 | |
E, J, 1 |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
list = [["A", "B", "C"], ["A", "C", "E"], ["E", "F", "D"], ["D", "A", "J"], ["E", "D", "J"]].map { |item| item.permutation(2).to_a.map(&:sort).uniq }.flatten(1) | |
combo = list.uniq.map {|c| c + [list.count(c)] } | |
combo |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Yeah I realized that after I posted it. Figured it didn't matter though since, like you, anyone who knows ruby knows that the assignment in line 2 and all of line 3 do nothing. They were left over from my testing where I was inspecting 'combo'