Python for everybody - Assignment 4.6

gistfile1.txt

def computepay(h,r):
    if h<=40:
        pay=h*r
    elif h>40:
        pay=40*r+(h-40)*r*1.5
	return(pay)

hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Enter rate:")
r = float(rate)
p = computepay(h,r)
print(p)

its works 100%.
def computepay(h,r):
if h<=40:
pay=hr
elif h>40:
pay=40r+(h-40)r1.5
return(pay)

hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Enter rate:")
r = float(rate)
p = computepay(h,r)
print("Pay",p)

This worked for me perfectly, most of the times it has to do with indentations, or Colons or " " improperly placed.
def computepay(h, r):
if hours <= 40:
pay = hours * rate
else:
pay = 40 * rate + (hours - 40) * rate * 1.5
return pay

hours = float(input("Enter hours: "))
rate = float(input("Enter rate per hour: "))

p = computepay(10, 20)
print("Pay", p)

Note: There are indentations in this code: if, else and returned must be aligned; pay, pay must also be aligned. If using python 3, hit the tab key once, which should place if right between f in def and space and c in computepay(h,r): The first pay should be right beneath hours of the if statement. The second pay should be beneath se of the else: and lastly return pay should be in alignment with else: so it should be if hours, else: and return pay aligned correctly and the same for pay by using the space bar in your pc. There two spaces after lines:6 and 10

def computepay(h, r):
if h <= 40:
pay = h * r
elif h > 40:
pay = 40 * r + (h - 40) * r * 1.5
return pay # Corrected indentation

Get user input for hours and rate

hrs = input("Enter Hours: ")
h = float(hrs) # Convert input to float
rate = input("Enter Rate: ")
r = float(rate) # Convert input to float

Calculate pay

p = computepay(h, r)

Print the result

print(p)

Explanation of Changes
Indentation: The return pay statement is now correctly indented to be part of the computepay function.
Input Handling: The input handling remains the same, converting the input strings to floats for calculations.