Python function to take GPS week and GPS seconds and return a UTC datetime string in the format "YYYY-MM-DD HH:MM:SS"

GPStoUTC.py

def weeksecondstoutc(gpsweek,gpsseconds,leapseconds):
    import datetime, calendar
    datetimeformat = "%Y-%m-%d %H:%M:%S"
    epoch = datetime.datetime.strptime("1980-01-06 00:00:00",datetimeformat)
    elapsed = datetime.timedelta(days=(gpsweek*7),seconds=(gpsseconds+leapseconds))
    return datetime.datetime.strftime(epoch + elapsed,datetimeformat)
    
weeksecondstoutc(1811,164196.732,16) ## --> '2014-09-22 21:36:52'

Hi, there may be a small mistake in the 5th line because GPS is ahead of UTC. Additionally, the calendar module is never used.
Optimized code:

def weeksecondstoutc(gpsweek,gpsseconds,leapseconds):
    import datetime
    datetimeformat = "%Y-%m-%d %H:%M:%S"
    epoch = datetime.datetime.strptime("1980-01-06 00:00:00",datetimeformat)
    elapsed = datetime.timedelta(days=(gpsweek*7),seconds=(gpsseconds-leapseconds))
    return datetime.datetime.strftime(epoch + elapsed,datetimeformat)
    
weeksecondstoutc(1811,164196.732,16) ## --> '2014-09-22 21:36:20'

Great! I have a question, how do you get the leap seconds?

@LuisDLCP I get every leap second in Leap_Second.dat from the website International Earth rotation and Reference systems Service.
And GPS was zero at 1980-01-06 00:00:00, so we can count from the line which is the 20th leap second in UTC. In other words, the leap second of GPS is 35-19=16 on September 22, 2014.
Here is a website that displays the local time, UTC, and GPS time real-timely.

Thank you @zfb132!