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January 27, 2016 18:51
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A Speed Comparison Of C, Julia, Python, Numba, and Cython on LU Factorization
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// lu.c | |
inline int _(int row, int col, int rows){ | |
return row*rows + col; | |
} | |
void det_by_lu(double *y, double *x, int N){ | |
int i,j,k; | |
*y = 1.; | |
for(k = 0; k < N; ++k){ | |
*y *= x[_(k,k,N)]; | |
for(i = k+1; i < N; ++i){ | |
x[_(i,k,N)] /= x[_(k,k,N)]; | |
} | |
for(i = k+1; i < N; ++i){ | |
#pragma omp simd | |
for(j = k+1; j < N; ++j){ | |
x[_(i,j,N)] -= x[_(i,k,N)] * x[_(k,j,N)]; | |
} | |
} | |
} | |
} | |
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function det_by_lu(y, x, N) | |
y[1] = 1. | |
for k = 1:N | |
y[1] *= x[k,k] | |
for i = k+1:N | |
x[i,k] /= x[k,k] | |
end | |
for j = k+1:N | |
for i = k+1:N | |
x[i,j] -= x[i,k] * x[k,j] | |
end | |
end | |
end | |
end | |
function run_julia(y,A,B,N) | |
loops = max(10000000 // (N*N), 1) | |
print(loops) | |
for l in 1:loops | |
B[:,:] = A | |
det_by_lu(y, B, N) | |
end | |
end | |
y = [0.0] | |
N=5 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=5 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=10 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=30 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=100 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=200 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=300 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=400 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=600 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
N=1000 | |
A = rand(N,N) | |
B = zeros(N,N) | |
@time run_julia(y,A,B,N) | |
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And here's some improvements to your Julia code. The result of the last expression is vector of elapsed times.
You can also add
@fastmath @simd
indet_by_lu!
after@inbounds
it gives small speedupUPD. Forgot to say that you may also take a look at BenchmarkTools.jl, that provides
@benchmark
and@btime
macro