Code Golf

A-Code-Golf-Challenge.md

Code Golf Challenge

• Write a program that counts down from 10 (and can either end at 0|1) -- your choice
• Prints one number per line
• Can optionally accept a command-line argument
• No looping constructs are allowed, such a for and while
• Make it as short as possible, but still readable
• Please reply with your own solutions, include the programming language
• • Include instructions on how to compile && run

countdown.c

#include <stdio.h> // compile & run: gcc -Wall countdown.c -o countdown && ./countdown
int n=10;int main(int a,char*b[]){printf("%d\n",n)&&--n&&main(n,NULL);}

countdown.go

// run: go run countdown.go
package main;func main(){n(10)};func n(i int){println(i);if i>1{n(i-1)}}

countdown.js

// node
n=10;main=_=>(console.log(n),n>0&&n--&&main());main()

// or...
n=10;main=_=>{console.log(n);n>0&&n--&&main()};main()

countdown.py

import sys # run: python3 countdown.py 10
def main(n:int): print(n) or n-1 and main(n-1)
main(int(sys.argv[1]))

countdown.rs

fn main(){let _=(10..=1).rev().map(|n|println!("{}",n)).collect::<Vec<_>>();}

countdown.sh

# run ./countdown.sh 10
echo $1&&(($1-1))&&$0 $(($1-1))

countdown.zig

pub fn main()void{if(@as(u8,10)>0)_=print("{}\n",.{10})||(main()catch{});}

countdown2.go

package main;var n=10;func main(){print(n,"\n");if n>0{n-=1;main()}}

countdown2.py

# this is a list comprehension, which interally does use a for loop
# run: python3 countdown2.py
_=[print(n)for n in range(10,0,-1)]