Difference between findAny() and findFirst() in Java 8

findAny_vs_findFirst.groovy

import java.util.concurrent.ForkJoinPool

println ForkJoinPool.commonPool().getParallelism()

def l = Arrays.asList("A","B","C","D")
// def l = new LinkedList<String>(["B","A","C"])

println Runtime.getRuntime().availableProcessors()


// def r = l.stream().parallel().filter { e -> e != "B" } .findAny()
//  def s = l.stream().parallel().filter { it != "B"} .findFirst()


def r = l.parallelStream()
 .filter { e ->
    println "[findAny]Thread: ${Thread.currentThread().getName()}"
    e != "B"
 }
 .findAny()
 
 
 def s = l.parallelStream()
 .filter { e ->
    println "[findFirst]Thread: ${Thread.currentThread().getName()}"
    e != "B"
 }
 .findFirst()
 
println l
println r.get()  // sometime A or C
println s.get()  // always A

Perfect example! Thank you!

@jiahut Question though, if this was NOT a parallel stream, hypothetically, "findAny()" would indeed ALWAYS encounter the 'A' first, correct? Since the source is a Array (Specifically, an ORDERED collection) and the "stream" function would maintain that order, correct?

in a sequential stream scenario, findAny() and findFirst() would produce identical results for this ordered collection.