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July 17, 2014 15:44
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[ Javascript ] - 20140718-题目1
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请把一组有规律的单词拼接起来,规则为: | |
前一个单词的结尾应该与下一个单词的首字母相同。 | |
如: aloha, dog, arachnid, gopher, tiger, rat | |
结果为:aloha-arachnid-dog-gopher-rat-tiger. | |
PS: | |
1. 回复时注意加上下面这句话,才会有语法高亮或格式缩进。 | |
```javascript | |
// you code | |
``` | |
2. 粘贴代码时请使用shift+tab,缩进前面的空白。 |
我很少用 js写程式,各位常用 js,一定可以再优化
<script>
var arr = ['aloha', 'dog', 'arachnid', 'gopher', 'tiger', 'rat'];
// 印出数组
document.write('<br>数组:');
for (var i =0 ;i<arr.length;i++) {
document.write(arr[i]+', ');
}
document.write('<br>');
var txt1="";
var fun = function(arr1) {//递归方式计算
arr_length = arr1.length;
// 印出数组
//document.write('<br>数组:');
//for (var i =0 ;i<arr_length;i++) {
// document.write(arr1[i]+', ');
//}
//document.write('<br>arr.length : ' + arr.length + ', 比对字符串:' + arr1[0]);
//document.write('->'+arr1[0]); // 印出讯息予用户
txt1 = txt1 + '-' + arr1[0];
str_x = right(arr1[0],1);
for (var i =1 ;i<arr_length;i++){
str_y = left(arr1[i],1);
if (str_x==str_y){
// document.write ('<br>'+i+' '+arr1[i]+' : '+str_x+' '+ str_y);
// document.write('<br>'+i+'-'+arr1[i]); // 印出讯息予用户
Str_temp = arr1[i] // 找到字符串的元素,移动到此数组的第1个
arr1.splice(0,1); // 此数组 移除 第一个元素
arr1.splice(i-1,1); // 此数组,找到字符串的元素, 移除
arr1.unshift(Str_temp); //此数组,加入第一个是找到的字符串
return ( fun(arr1)); // 递归
}
}
document.write ('<br>=>'+txt1.substring(1,txt1.length));
}
fun(arr);
function left(str, num)
{
return str.substring(0,num)
}
function right(str, num)
{
return str.substring(str.length-num,str.length)
}
</script>
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随机打乱数组, 对打乱后的数组进行校验,总会有一种情况是符合条件的。