Created
August 29, 2014 00:10
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[ Javascript ] - 20140829-题目1
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用最优的代码实现: | |
如何判断出字符串 b 中的每一个字符,在 a 中是否存在。 | |
比如: | |
var a = 'lkjgfaoids'; | |
var b = 'adc'; | |
ad存在,c不存在。 | |
PS: | |
1. 回复时注意加上下面这句话,才会有语法高亮或格式缩进。 | |
```javascript | |
// you code | |
``` | |
2. 粘贴代码时请使用shift+tab,缩进前面的空白。 |
cheng470
commented
Aug 29, 2014
function checkExist(a, b) {
var exist = b.split('').filter(function (v) {return a.indexOf(v) > -1});
var noExist = b.split('').filter(function (v) {return a.indexOf(v) === -1});
console.log(exist.join('') + '存在', noExist.join('') + '不存在');
}
var a = 'lkjgfaoids';
var b = 'adc';
checkExist(a,b);
function test(a,b){
var c=b ,d=b;
for(var i=0;i<a.length;i++){
c = c.replace(new RegExp(a[i],"gm"),'')
}
for(var j=0;j<c.length;j++){
d = d.replace(new RegExp(c[j],"gm"),'');
}
console.log("存在:"+d + " 不存在:"+c);
}
var a = 'lkjgfaoids';
var b = 'adc';
test(a,b)
var a = 'lkjgfaoids';
var b = 'adc';
a = a.split('');
b = b.split('');
var arr1 = a.filter(function(v) { return b.indexOf(v) > -1; }) // 保存存在的
var arr2 = b.filter(function(v) { return arr1.indexOf(v) == -1; })
console.log( arr1.join('')+ "存在," + arr2.join('')+"不存在" )
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