Created
August 4, 2017 03:51
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There must be a better way to compute this...
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import random | |
random.seed() | |
def flip(): | |
return random.choice([True, False]) | |
def run(): | |
b = flip() | |
n = 1 | |
while True: | |
(a, b) = (b, flip()) | |
n += 1 | |
if a and b: | |
return n | |
runs = 100000 | |
def count(): | |
counts = [0] * 100 | |
for i in xrange(0, runs): | |
n = run() | |
if n < len(counts): | |
counts[n] += 1 | |
return counts | |
counts = count() | |
for n in range(2,10): | |
print round(float(counts[n]) / runs * 2**n) |
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