react-unknown-prop.md

The unknown-prop warning will fire if you attempt to render a DOM element with a prop that is not recognized by React as a legal DOM attribute/property. You should ensure that your DOM elements do not have spurious props floating around.

There are a couple of likely reasons this warning could be appearing:

1. Are you using {...this.props} or cloneElement(element, this.props)? Your component is transferring its own props directly to a child element (eg. https://facebook.github.io/react/docs/transferring-props.html). When transferring props to a child component, you should ensure that you are not accidentally forwarding props that were intended to be interpreted by the parent component.

2. You are using a non-standard DOM attribute on a native DOM node, perhaps to represent custom data. If you are trying to attach custom data to a standard DOM element, consider using a custom data attribute (https://developer.mozilla.org/en-US/docs/Web/Guide/HTML/Using_data_attributes).

3. React does not yet recognize the attribute you specified. This will likely be fixed in a future version of React. However, React currently strips all unknown attributes, so specifying them in your React app will not cause them to be rendered.

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To fix this, composite components should "consume" any prop that is intended for the composite component and not intended for the child component. Example:

Bad: Unexpected layout prop is forwarded to the div tag.

function MyDiv(props) {
  if (props.layout === 'horizontal') {
    // BAD! Because you know for sure "layout" is not a prop that <div> understands.
    return <div {...props} style={getHorizontalStyle()} />
  } else {
    // BAD! Because you know for sure "layout" is not a prop that <div> understands.
    return <div {...props} style={getVerticalStyle()} />
  }
}

Good: The spread operator can be used to pull variables off props, and put the remaining props into a variable.

function MyDiv(props) {
  const { layout, ...rest } = props
  if (layout === 'horizontal') {
    return <div {...rest} style={getHorizontalStyle()} />
  } else {
    return <div {...rest} style={getVerticalStyle()} />
  }
}

Good: You can also assign the props to a new object and delete the keys that you're using from the new object. Be sure not to delete the props from the original this.props object, since that object should be considered immutable.

function MyDiv(props) {

  const divProps = Object.assign({}, props);
  delete divProps.layout;
  
  if (props.layout === 'horizontal') {
    return <div {...divProps} style={getHorizontalStyle()} />
  } else {
    return <div {...divProps} style={getVerticalStyle()} />
  }
}

I just want to make a note, that syntax

const { layout, ...rest } = props

is not a part of ES6, but currently only Stage 2 proposal of ES7.

So, for real life usage there's only delete variant or you can use Lodash .omit(), .pick() functions.

@zediah did you ever come up with a solution? Creating an element definitely isn't it, and it can be nice to not have to add additional components to the tree.

Hy, is there a way where I can specifically cut down props which are not required for my html element? For example I have a parent Component which wraps which wraps standard HTML input component . When I pass props from wrapper I want to remove props in CustomInput which are not standard html props for input. Apart from checking every valid props is there any other way ?

extract your own props from it

const { isMenuOpen, ...props } = this.props

then pass props to your component (without this)

<Header {...props} />

Are they any different ways to handle this problem in 2021? In my case, the props sent to a child component are dynamic and unknown at runtime. So I need a way of (a) stripping them out automagically or (b) suppressing the warning.
(a) would be better! Ideas?

What's the "source of truth" for the known props?