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  | // 1. Determine if two numbers, x and y, are relatively prime. Compute for T(n) of your solution. | |
| // Two integers are relatively prime if they share no common positive factors (divisors) except 1. | |
| // 2. Compute for T(n): | |
| for (int i = 1; i <= n; i++) { | |
| a = x - y + 7 * b; | |
| for (int j = 1; j <= n; j++) { | |
| x = a + b; | |
| for (int k = j; k <= n; k++) { | |
| cout << "hi" << endl; | |
| } | |
| } | |
| } | |
| // 3. Compute for T(n): | |
| for (int i = 1; i <= n; i++) | |
| for (int j = i; j <= n; j++) | |
| for (int k = j; k <= n; k++) | |
| cout << "hey!" << endl; | |
| // 4. Simplify the following recurrence relation: T(n) = 2T(n / 2) + n | |
| // For reference - common recurrence relations and their solutions: | |
| // http://papl.cs.brown.edu/2016/predicting-growth.html#%28part._solving-recurrences%29 | 
  
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