Created
October 11, 2012 19:08
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import numpy as np | |
import theano | |
import theano.tensor as tt | |
# this is the input | |
inp = np.arange(10).reshape(-1,1) | |
print 'this is the input: {}'.format(inp) | |
# this is the expected output | |
exp_out = np.zeros((10,1)); exp_out[4:] = inp[:-4] | |
print 'this is the expected output: {}'.format(exp_out) | |
def onestep(x, x_tm4): | |
""" | |
This function has two inputs and two outputs. x represents the sequence at | |
time t. That value is returned as the first output. The first output is | |
then recycled with a lag of 4 to create the second input, x_tm4. The second | |
input is passed through to become the second output. Getting the second | |
output is the objective of this exercise.""" | |
return x, x_tm4 | |
seq = tt.matrix() | |
initial_value = theano.shared(np.zeros((4,1))) | |
outputs_info = [{'initial' : initial_value, 'taps' : [-4]}, None] | |
results, updates = theano.scan(fn = onestep, | |
sequences = seq, | |
outputs_info = outputs_info) | |
f1 = theano.function([seq], results) | |
print 'Expected: the input and its lag. Returned: the input and its lag.' | |
print f1(inp) | |
f2 = theano.function([seq], results[0]) | |
print 'Expected: just the input. Returned: just the input.' | |
print f2(inp) | |
f3 = theano.function([seq], results[1]) | |
print 'Expected: just the lag. Returned: just the input!' | |
print f3(inp) |
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